Replace vba access

Replace vba access DEFAULT

The VBA Replace function is a function which you can use in your code to replace one set of string characters with another set of string characters, or to replace a set of string characters with an empty string.

For example, you may have a paragraph of text which refers to the city “New York" repetitively and you may wish to change this city to “Boston.” You can use the replace function to find all instances of “New York" and replace those instances with “Boston"

The syntax of the replace function is:

Where the arguments that are contained within square brackets are optional and do not need to be utilized if not required.

The Expression is the string of text that you would be searching within.

The Find is the string you would be searching for eg: “New York"

The Replace is the string of text that you would be replacing the string in the Find.

The [Start] is the position in the Expression string that you wish to start at.  If omitted (which is usually is), this starts at position 1 – so the beginning of the string.

The [Count] is the number of times you want the function to find the Find string, and replace it with the Replace string.  This is usually omitted and the function will search the entire Expression string until it no longer find the Find string.

The [Compare] is the type of data you are looking for. This is usually omitted, and the default of binary data (vbBinaryCompare) is used. However, you can specify it to vbTextCompare or vbDatabaseCompare if required.

For example,

Sub ReplaceText Dim strNew As String Dim strOld As String 'populate the original string strOld = "The show is going to be set in New York. New York is a vibrant city in the state of New York in the USA." strNew = Replace(strOld, "New York", "Buffalo") MsgBox strNew End Sub

When I run the code above, the following message box is displayed

Message box saying "The show is going to be set in Buffalo. Buffalo is a vibrant city in the state of Buffalo in the USA."Pin it!Share on Facebook

Now, as Buffalo isn’t a state – that is not quite correct!  

We can therefore limit the replace function to just replace the first two instances of New York, while leaving the first one as it is.

Sub ReplaceText Dim strNew As String Dim strOld As String 'populate the original string strOld = "The show is going to be set in New York. New York is a vibrant city in the state of New York in the USA." strNew = Replace(strOld, "New York", "Buffalo",1,2) MsgBox strNew End Sub
The state is now listed as New YorkPin it!Share on Facebook

In the above example, we are starting at position 1 of the variable strOld – but are only looking for two instances of the string that we wish to find.

If we only wanted to return the second sentence and not both sentences in the code above, we could amend the code to look like this:

Sub ReplaceText Dim strNew As String Dim strOld As String 'populate the original string strOld = "The show is going to be set in New York. New York is a vibrant city in the state of New York in the USA." strNew = Replace(strOld, "New York", "Buffalo",42,1) MsgBox strNew End Sub
Buffalo is a vibrant city in the state of New York in the USA.Pin it!Share on Facebook

As starting at position 42 would give us two occurrences of the word “New York", we would need to amend the [Count] argument to only look for 1 occurrence.

Leaving out the [Compare] option means that the Replace function will only find text that is in the correct case syntax.  For example, if we look for New York, but the text is new york – then the text will not be found.  If we want to make sure ALL instances of New York are found, regardless of upper or lower case, then we need to use vbTextCompare.  This is particularly useful when are looking through information that has been manually entered and may be subject to human error.

This code below:

Sub ReplaceText Dim strNew As String Dim strOld As String 'populate the original string strOld = "The show is going to be set in New York. New York is a vibrant city in the state of new york in the USA." strNew = Replace(strOld, "New York", "Buffalo",,,[vbTextCompare]) MsgBox strNew End Sub

Will return this message box below:

Message if we use vbTextComparePin it!Share on Facebook

However, if we leave out [vbTextCompare] and therefore we would be using vbBinaryCompare, then this is what would be returned in the message box.

Results of binarycomparePin it!Share on Facebook

The [vbDatabaseCompare] option is only available to be used in Microsoft Access and where searching through Access data is based on the locale ID of the database table.  You can read more about this at https://msdn.microsoft.com/en-us/library/aa266181(v=vs.60).aspx

In addition to replacing one string with another, the replace function can be an extremely useful function to use for data cleaning when looping through information held in Excel spreadsheets or Access tables. Often, imported data will contain characters that are not required, causing the data to need “cleaning.” In instances such as that, the replace function can be invaluable.

For example, in the VB snippet below, information could be passed to the CleanSpaces function where the information is meant to be a number, but the information may contain a space – thus turning the information from a number value into a string value – such as “2 000”

Sub CleanMe() MsgBox CleanSpaces("2 000") End Sub Function CleanSpaces(strV As String) As Double strV = Replace(strV, " ", "") CleanSpaces = CDbl(strV) End Function

The replace function is looking for a space in the string value and replacing it with nothing, thus enabling the string value to be converted to a double value.

In this article I have explained about the value of using the Replace function in VBA and the importance that the different arguments of the Replace function. It is also extremely useful in cleaning data that you may have imported from CSV files into Excel and Access where the information may contain characters that you do not want in your data – this could include dollar signs, percent signs, spaces and apostrophes to name just a few.

Tagged with:Functions, Replace, VBA, vba replace

Sours: https://software-solutions-online.com/vba-replace-function/

Replace function

Returns a string, which is a substring of a string expression beginning at the start position (defaults to 1), in which a specified substring has been replaced with another substring a specified number of times.

Syntax

Replace(expression, find, replace, [ start, [ count, [ compare ]]])


The Replace function syntax has these named arguments:

PartDescription
expressionRequired. String expression containing substring to replace.
findRequired. Substring being searched for.
replaceRequired. Replacement substring.
startOptional. Start position for the substring of expression to be searched and returned. If omitted, 1 is assumed.
countOptional. Number of substring substitutions to perform. If omitted, the default value is -1, which means, make all possible substitutions.
compareOptional. Numeric value indicating the kind of comparison to use when evaluating substrings. See Settings section for values.

Settings

The compare argument can have the following values:

ConstantValueDescription
vbUseCompareOption-1Performs a comparison by using the setting of the Option Compare statement.
vbBinaryCompare0Performs a binary comparison.
vbTextCompare1Performs a textual comparison.
vbDatabaseCompare2Microsoft Access only. Performs a comparison based on information in your database.

Return values

Replace returns the following values:

IfReplace returns
expression is zero-lengthZero-length string ("")
expression is NullAn error.
find is zero-lengthCopy of expression.
replace is zero-lengthCopy of expression with all occurrences of find removed.
start > Len(expression)Zero-length string. String replacement begins at the position indicated by start.
count is 0Copy of expression.

The return value of the Replace function is a string, with substitutions made, that begins at the position specified by start and concludes at the end of the expression string. It is not a copy of the original string from start to finish.

See also

Support and feedback

Have questions or feedback about Office VBA or this documentation? Please see Office VBA support and feedback for guidance about the ways you can receive support and provide feedback.

Sours: https://docs.microsoft.com/en-us/office/vba/language/reference/user-interface-help/replace-function
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MS Access Replace() Function

❮ MS Access Functions

Example

Replace "i" with "a" in the string:

SELECT Replace("My name is Willy Wonka", "i", "a") AS ReplaceString;

Try it Yourself »

Definition and Usage

The Replace() function replaces a substring within a string, with another substring, a specified number of times.

Syntax

Replace(string1, find, replacement, start, count, compare)

Parameter Values

ParameterDescription
string1Required. The original string
findRequired. The substring to search for in string1
replacementRequired. The substring to replace find in string1
startOptional. The start position in string1 to begin the search. If omitted, start is 1
countOptional. The number of replaces to perform. If omitted, it will replace all occurrences of find with replacement
compareOptional. The type of string comparison.

Possible values:
-1: Use the setting of Option Compare
0: Binary comparison
1: Textual comparison
2: Comparison based on info in your database

Technical Details

Works in:From Access 2000

❮ MS Access Functions


Sours: https://www.w3schools.com/sql/func_msaccess_replace.asp
Access 2010 - Find And Replace Field Values - Tutorial

Access VBA | How to replace parts of a string with another string

I was reading this thread and would like to add information even though it is surely no longer timely for the OP.

BiggerDon above points out the difficulty of rote replacing "North" with "N". A similar problem exists with "Avenue" to "Ave" (e.g. "Avenue of the Americas" becomes "Ave of the Americas": still understandable, but probably not what the OP wants.

The replace() function is entirely context-free, but addresses are not. A complete solution needs to have additional logic to interpret the context correctly, and then apply replace() as needed.

Databases commonly contain addresses, and so I wanted to point out that the generalized version of the OP's problem as applied to addresses within the United States has been addressed (humor!) by the Coding Accuracy Support System (CASS). CASS is a database tool that accepts a U.S. address and completes or corrects it to meet a standard set by the U.S. Postal Service. The Wikipedia entry https://en.wikipedia.org/wiki/Postal_address_verification has the basics, and more information is available at the Post Office: https://ribbs.usps.gov/index.cfm?page=address_info_systems

answered Jan 14 '16 at 16:12

Sours: https://stackoverflow.com/questions/8550240/access-vba-how-to-replace-parts-of-a-string-with-another-string

Access replace vba

Replace

Replace a sequence of characters in a string.

Syntax Replace(string, findStr, ReplaceStr, [start, [count, [compare]]]) Key string The initial text string. findStr The text string to search for in string. ReplaceStr The new string that will replace findStr in string. start The position in string to begin the search. default=start (character 1) count The number of occurrences to replace. default=replace all occurrences. compare The comparison mode (Binary/Text)

The Replace() function can be used in VBA or in an SQL query.

Examples

Dim strDemo as String
strDemo = Replace("Don Quijote", "Quij", "Quix")
MsgBox StrDemo
Returns: Don Quixote

“The shooting of the movie is the truth part and the editing of the movie is the lying part, the deceit part” ~ Paul Hirsch

Related:

InStr - Return the position of one string within another.


 

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Sours: https://ss64.com/access/replace.html
Microsoft Access REPLACE Function, Update Query, TechHelp Q\u0026A

Overview of VBA Replace Function:

VBA Replace function is categorized as a Text/String function in VBA. It is a built-in function in MS Office Excel. It replaces a substring with another string in a given string. It has three required parameters and three optional parameters. If expression is Null, then the function returns an error. If expression has length, then it returns an empty string. This function could be used as a VBA function and a Excel Worksheet function(It has different syntax in Excel). The Replace function can be used in either procedure or function in a VBA editor window in Excel. We can use this VBA Replace function any number of times in any number of procedures or functions. In the following section we learn what is the syntax and parameters of the Replace function, where we can use this Replace function and real-time examples in VBA.

Table of Contents:

Syntax of VBA Replace Function

The syntax of the VBA Replace function is

Replace(Expression, Find, Replace, [Start], [Count], [Compare])

Note: This Replace function returns a string.

Parameters or Arguments

This function has three mandatory parameters and three optional parameters for the Replace Function.
Where

Expression: An Expression is a mandatory argument. It represents a string expression you want to replace substring in.
Find: Find is a mandatory argument. It represents a substring which we want to find or search within an expression.
Replace: Replace is a mandatory argument. It represents a substring which we want to replace within an expression.
Start: Start is an optional parameter. Default value is ‘1’. It represents the position in expression to start search.
Count: Count is an optional parameter. It represents the number of occurrences to replace substring within an expression. Default value is ‘-1’. If we ignore, it will replace all occurrences of substring with another specified substring.
Compare: Compare is an optional parameter. It represents a numeric value. It specifies the type of comparison to evaluate the substrings. This argument can have anyone of the following value. Default comparison is ‘vbBinaryCompare’.

VBA ConstantValueDescription
vbUseCompareOption-1Performs a comparison using the Option Compare statement.
vbBinaryCompare0performs a binary comparison
vbTextCompare1performs a text comparison
vbDatabaseCompare2performs a database comparison. It applies only in MS Access.

Where we can apply or use the VBA Replace Function?

We can use this VBA Replace function in MS Office 365, MS Excel 2016, MS Excel 2013, 2011, Excel 2010, Excel 2007, Excel 2003, Excel 2016 for Mac, Excel 2011 for Mac, Excel Online, Excel for iPhone, Excel for iPad, Excel for Android tablets and Excel for Android Mobiles.

Example 1: Replace all occurrences of substring “F1” with “Help”

Here is a simple example of the VBA Replace function. This below example macro returns a string. The output of the below macro is ‘VBAHelp’.

'Replace all occurrences of substring "F1" with "Help". Sub VBA_Replace_Function_Ex1() Dim sString As String, sSubString As String sString = "VBAF1" sSubString = Replace(sString, "F1", "Help") MsgBox "Replace F1 with Help :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the first example output.
VBA Replace Function

Example 2: Replace all occurrences of substring “Help” with “F1”

Here is a simple example of the VBA Replace function. This below example macro returns a string. The output of the below macro is ‘VBAF1’.

'Replace all occurrences of substring "Help" with "F1". Sub VBA_Replace_Function_Ex2() Dim sString As String, sSubString As String sString = "VBAF1" sSubString = Replace(sString, "Help", "F1") MsgBox "Replace Help with F1 :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the second example output.
VBA Replace Function

Example 3: Replace all occurrences of substring “F1” with “Help” starting from position 13

Here is a simple example of the VBA Replace function. This below example macro returns a string. It ignores specified ‘N(start)’ characters, when we specify start position. The output of the below macro is ‘VBAHelp-VBAHelp-VBAHelp’.

'Replace all occurrences of substring "F1" with "Help" starting from position 13 Sub VBA_Replace_Function_Ex3() Dim sString As String, sSubString As String sString = "VBAF1-VBAF1-VBAF1-VBAF1-VBAF1" sSubString = Replace(sString, "F1", "Help", 13) MsgBox "Replace F1 with Help :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the third example output.
VBA Replace Function

Example 4: Replace all occurrences of substring “F1” with “Help” starting from position 13 and keep whole string

Here is a simple example of the VBA Replace function. This below example macro returns a string. It ignores specified ’13(start)’ characters, when we specify start position. In this example we are using left function to extract left most characters from the given string. And adding the output to original output. Here is the final output of the below macro is ‘VBAF1-VBAF1-VBAHelp-VBAHelp-VBAHelp’.

'Replace all occurrences of substring "F1" with "Help" starting from position 13 and keep whole string Sub VBA_Replace_Function_Ex4() Dim sString As String, sSubString As String sString = "VBAF1-VBAF1-VBAF1-VBAF1-VBAF1" sSubString = Left(sString, 12) & Replace(sString, "F1", "Help", 13) MsgBox "Replace F1 with Help :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the fourth example output.
VBA Replace Function

Example 5: Replace last occurrence of substring “F1” with “Help”

Here is a simple example of the VBA Replace function. This below example macro returns a string. Here is the final output of the below macro is ‘VBAF1-VBAF1-VBAF1-VBAF1-VBAHelp’.

'Replace last occurrence of substring "F1" with "Help" Sub VBA_Replace_Function_Ex5() Dim sString As String, sSubString As String sString = "VBAF1-VBAF1-VBAF1-VBAF1-VBAF1" sString = StrReverse(sString) sString = Replace(sString, StrReverse("F1"), StrReverse("Help"), , 1) sSubString = StrReverse(sString) MsgBox "Replace F1 with Help :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the fifth example output.
VBA Replace Function

Example 6: Remove all occurrences of substring ‘F1’

Here is a simple example of the VBA Replace function. This below example macro returns a string. It removes all occurrences of substring within a string. Here is the final output of the below macro is ‘VBA-VBA-VBA-VBA-VBA’.

'Remove all occurrences of substring 'F1' Sub VBA_Replace_Function_Ex6() Dim sString As String, sSubString As String sString = "VBAF1-VBAF1-VBAF1-VBAF1-VBAF1" sSubString = Replace(sString, "F1", "") MsgBox "Remove all occurences of F1 :" & sSubString, vbInformation, "VBA Replace Function" End Sub

Output: Here is the screen shot of the sixth example output.
VBA Replace Function

Instructions to use Macro Codes

Here are the step by step instructions to use the VBA Replace function in Excel VBA.

  • Open an Excel workbook.
  • Press Alt+F11 to open VBA Editor window.
  • Go to Insert menu and click on module from the available options.
  • Copy above specified macros to the VBA editor.
  • Select any procedure from above codes and click on ‘Run’ command or use Keyboard shortcut ‘F5’.

Complete List of VBA Functions:

Please click on below link to go back to see all List of VBA Functions.
List of VBA Functions

Sours: https://vbaf1.com/functions/replace/

You will also be interested:

* This function is case sensitive (by default).
* This function does not support wildcards (? and *).
* This function replaces all occurrences of the "find" text string.
* The return value of the Replace function is a string, with substitutions made, that begins at the position specified by start and concludes at the end of the expression string. It is not a copy of the original string from start to finish.
* If "expression" is Null, then Null is returned.
* If "expression = "" (zero length string), then a zero length string ("") is returned.
* If "find" = "" (zero length string), then "expression" is returned.
* If "replace = "" (zero length string), then all occurrences of "find" are removed.
* If "start" > Len("expression"), then a zero length string ("") is returned.
* If "start" is left blank, then it is assumed to be 1.
* If "count" = 0, then "expression" is returned.
* If "count" is left blank, then it is assumed to be -1, which means make all possible substitutions.
* If "compare" is left blank, then -1 is used. If there is no Option Compare statement provided then vbBinaryCompare (0) is used.
* If "compare" is Null, then an error occurs.
* This is an extremely slow function and should only be called when you know a replacement will take place.
* The reason this function is so slow is because a copy of the "expression" is always made even when there are no replacements.
* You can use the INSTR function to return the position of a substring within a larger string.
* You can use the JOIN function to return a text string containing all the elements in an array (using wildcard searches).
* You can use the SPLIT function to return the array containing a specified number of substrings (using wildcard searches).
* You can use the REPLACE$ function to return a String data type instead of Variant/String data type.
* For more information, refer to the Replacing Strings page.
* The equivalent .NET function is Microsoft.VisualBasic.Strings.Replace
* For the Microsoft documentation refer to docs.microsoft.com
Sours: https://bettersolutions.com/vba/functions/replace-function.htm


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